A pair of dice was rolled many times and the result appears below. Based upon these results, what is the experimental probability of rolling a number less than 10?

Question is incomplete.

The observation are as follows;

Outcome Frequency

2 3

3 --- 6

4 -- 8

5 --- 11

6 --- 14

7 16

8 --- 15

9 12

10 9

11 5

12 1

The probability of rolling a number less than 10 is 0.85

Step-by-step explanation:

The probability of rolling a number less than 10 is calculated as follows;

Let x = the observation.

We're asked to solve P(x<10).

This means that we consider only numbers of observation less that 10

P(x<10) = Number of required outcome/Number of possible outcome.

Number of required outcome is summation of all observation less than 10.

This is calculated as follows;

Number of required outcome = 3+6+8+11+14+16+15+12

Number of required outcome = 85.

Number of possible outcome = summation of all observation

Number of possible outcome = 3+6+8+11+14+16+15+12+9+5+1

Number of possible outcome = 100

P(x<10) = 85/100

P(x<10) = 0.85

Hence, the probability of rolling a number less than 10 is 0.85

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square