Collin invests 7700 in two different accounts the first paid 2% the second paid 9% in interest at the end of the first year he had earned $315 in interest how much was in each account

Collin invested $5529 in the account paying 2% and $2171 in the account paying 9% interest.

Explanation:

Let x be amount invested at 2%

So, 7700 - x will be the amount invested at 9%

0.02(x) + 0.09(7800 - x) = 315

0.02x + 702 - 0.09x = 315

-0.07x = -387

x = $5529

7700 - x = 7700 - 5529

             = $2171

Collin invested $5529 in the account paying 2% and $2171 in the account paying 9% interest.

e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic