One angle of a parallelogram measures 68°. What are the measures of the other three angles in the parallelogram?

Step-by-step explanation:

we know that opposite angles of parallelogram are equal so 1st angle and 3rd angle are 68 ° and 68°

And let 2nd and 4th angles be x and x

Now

68° + 68° + x + x = 360° <Being sum of angles of parallelogram >

136° + 2x = 360°

2x = 360° - 136°

2x = 224°

Therefore x = 112°

Now the measure of other angles are

68° , 112° , 68° and 112 °

2 angles 68⁰, the other 112⁰

Step-by-step explanation:

Two angles have 68⁰. And the other two have each 180⁰-68⁰=112⁰

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

12cm

the answer is d