The weights of the fish in a certain lake are normally distributed with a
mean of 20 lb and a standard deviation of 9. If 9 fish are randomly selected,
what is the probability that the mean weight will be between 17.6 and 23.6
Ib? Write your answer as a decimal rounded to 4 places

Solution

Normal distribution between 17.6 and 23.6

μ  = 20 lb

σ/x  = σ /√n = 9/√9 = 3

Distribution score for  17.6 = 17.6 - 20÷ 3 = - 0.8

Distribution score for 23.6 = 23.6 - 20÷ 3 = 1.2

p(mean weight between 17.6 and 23.6 for 9 fish) =

9(-0.8 ∠≠∠1.2) = 0.8849 - 0,2119 = 0.6730

P(17.6< xbar < 23.6) = P(-0.8 < t < 1.2 when df = 3) = 0.6730

9

step-by-step explanation:

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3