Which equation could be used to find m2J in AJKL?!
x= cos-" 4
x= cos"
8.8
β’...
Mathematics, 28.03.2020 23:27 DASASDAEDWEDA
Which equation could be used to find m2J in AJKL?!
x= cos-" 4
x= cos"
8.8
β’ x=sin"( 6:)
x = sin-1( 3.
Answers: 1
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One x-intercept for a parabola is at the point (1,0). use the factor method to find x-intercept for the parabola defined by the equation y=-3x^2+5x+2
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