Consider the functions f(x) = sin(2x) − 1 and g(x) = 2 cos2
(x), both with domain [0, π]. The line x = p intersects the graph of f in point A and the graph of g in point B. Calculate the value of p for which the length of segment AB is maximal.

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

imma say 16%. sorry if its wrong. i'm doing the same stuff right now

step-by-step explanation: