Find the nth degree polynomial function with real coefficients satisfying the given conditions. n=3; -2 and 2+3i are zeros; leading coefficient is 1.

  f(x) = x^3 -2x^2 +5x +26

Step-by-step explanation:

When p is a root, (x -p) is a factor.

If the polynomial has real coefficients, its complex roots come in conjugate pairs. Then the linear factorization for the given roots is ...

  f(x) = (x +2)(x -2-3i)(x -2+3i) = (x +2)(x^2 -4x +13)

  f(x) = x^3 -2x^2 +5x +26

multiple all that

step-by-step explanation:

27×17

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