Find the average value of the function over the given interval and all value (s) in the interval for which the function equals its average value f(u)=(u^2+4)/(u^2), 1≤ u≤ 7.

A. The average is 10/21 and the point at which the function is equal to its mean value is √7
B. The average is 11/7 and the point at which the function is equal to its mean value is √7
C. The average is 11/28 and the point at which the function is equal to its mean value is √7 and -√7
D. The average is 11/7 and the point at which the function is equal to its mean value is √7 and -√7

no, because the sides are not congruent

1 3 5

step-by-step explanation:

i took the test: )

the answer is 62.8 cubic units

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: