Find the area of this shape

200+40=240 sq units

Step-by-step explanation:

The rectangle's area is 200 sq units because 10 times 20 = 200

If you take both the triangles and put them together they form a smaller rectangle. The smaller rectangles height is 4 (given) and the base is 10 (because its half of the bigger rectangles base. You do base times height (4 times 10) and you get 40

Big Rectangle Area: 200

Small rectangle Area: 40

Total 240 (200+40)

i used to know how to do this in 7th but i forget easily

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°