A cylindrical swimming pool has a diameter of 16 feet and a height of 3 feet. How many gallons of water can the pool contain? Round your answer to the nearest whole number. (1 ft3 ≈ 7.5 gal)

The cylindrical swimming pool contain 4512 gallons of water, if a pool diameter has a diameter of 16 feet and a height of 3 feet.

Step-by-step explanation:

       The given is,

                Diameter of swimming pool is 16 feet

                Height of swimming pool is 3 feet

Step:1

        Formula for volume of cylinder is,

                            ........................(1)

       Where, r - Radius

                    h - Height

       Formula for radius,

                                             =

                                          r = 8 feet

Step:2

         From equation (1)

                                     V   cubic feet

Step:3

          From given ( 1 cubic feet = 7.5 gallons )

                                    V ≅ 4524 gallons

Result:

          The cylindrical swimming pool contain 4512 gallons of water, if a pool diameter has a diameter of 16 feet and a height of 3 feet.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2