What is the first step in solving the following equation

(x+2)(x-3)=0. PLEASE HELP ME QUICK ONLY HAVE 5 MINUTES
1.plug zero for x
2. solve for x
3. set each binomial factor equal to zero
4. foil

The first step in solving the equation is "set each binomial factor equal to zero" ⇒ 3

Step-by-step explanation:

To solve a quadratic equation y = ax² + bx + c

∵ The equation is (x + 2)(x - 3) = 0

∵ The equation equated by 0

∵ It is factored into 2 binomial factors (x + 2) and (x - 3)

- The next step is equated each factor by 0 to find the values of x

∴ The 1st step in solving (x + 2)(x - 3) = 0 is set x + 2 = 0 and

   x - 3 = 0

The first step in solving the equation is "set each binomial factor equal to zero"

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

22 dimes and 9 nickels

step-by-step explanation: