A circle has diameter of 11cm
A square has side length of 7cm
Use pythagoras’ Theorem to show that the square will fit inside the circle without ruching the edge of the circle.

Any suggestions would be greatly appreciated ThankYou!

Since length of diagonal (   ) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.

Step-by-step explanation:

Here we have , A circle has diameter of 11 cm  A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:

We know the concept that for any square to fit inside the circle without touching the edge of circle  , diagonal of square must be less than diameter of circle  . Let's find out length of diagonal by using Pythagoras Theorem :

For a square ,

⇒

⇒

⇒

⇒

Since length of diagonal (   ) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.

the least common denominatore of 7 and 2 is 9

step-by-step explanation:

7+2=9

1 + (6 / x - 1)

step-by-step explanation:

divide using polynomial division.