Write the equation of a line that passes through the point (2,-1) and is parallel to the line y=-2/5x+3.

y + 1 = 2/5(x - 2), or y = 2/5x - 9/5

Step-by-step explanation:

for this you'll need point-slope form, which is:

y - y1 = m(x - x1)

m = slope

the slope is 2/5, because parallel lines have the same slope.

plug values in:

y - (-1) = 2/5(x - 2)

y + 1 = 2/5(x - 2)

if you want this in mx + b form:

y + 1 = 2/5(x - 2)

y + 1 = 2/5x - 4/5

y = 2/5x - 9/5

45

step-by-step explanation:

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: