If the discriminate of a quadratic equation is equal to -8 which statement describes the roots

Roots of the quadratic Equation are not real. Roots are Complex Conjugates.

Step-by-step explanation:

Given: Discriminant of the a Quadratic Equation = -8

ax² + bx + c = 0 is standard form of quadratic equation, then the discriminant is given as follows:

D = b² - 4ac

we know that if,

1). D > 0 then Roots of the Quadratic equations are Real and Distinct.

2). D = 0 then Roots of the Quadratic equations are Real and Equal.

3). D < 0 then Roots of the Quadratic equations are not Real . They are complex conjugate.

So, for the given Discriminant we have Roots of the quadratic Equation are not real. Roots are Complex Conjugates.

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right