Branden and Pete each play running back. Branden carries the ball 75 times for 550 yards, and Pete has 42 carries for 380 yards. Who runs farther per carry

Pete ran farther per carry.

Step-by-step explanation:

Given:

Number of carries by Branden = 75

Number of yards ran by Branden = 550 yards.

Number of carries by Pete = 42

Number of yards ran by Pete = 380 yards.

We need to find who ran farther per carry.

Solution:

Now we will find the Distance per carry.

Distance per carry is equal to Number of yards ran by Branden divided by Number of carries by Branden.

framing in equation form we get;

Distance ran per carry by Branden =

Distance per carry is equal to Number of yards ran by Pete divided by Number of carries by Pete.

framing in equation form we get;

Distance ran per carry by Pete =

From we can see that;

Pete ran 9.04 yards/carry while Branden ran 7.33 yards/carry.

Hence Pete ran farther per carry.

something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).

a. is correct