A student writes the equation for a line that has a slope of -6 and passes through the point (2, –8).

y -(-8) = -6(x - 2)

y -(-8) = -6x + 12

y -(-8) + 8 = -6x + 12 + 8

y = -6x + 20

Explain why the work is not correct.

The error in the students work is

y -(-8) + 8 = -6x + 12 + 8

subtracting a negative is adding

y+8

They should subtract 8 from each side instead of adding 8 to each side

Step-by-step explanation:

We can use point slope form since we are given a point and the slope

y-y1 = m( x-x1)

y--8 = -6(x-2)

y+8 = -6(x-2)

Distribute the -6

y+8 = -6x+12

Subtract 8 from each side

y+8-8 = -6x+12-8

y = -6x+4

The error in the students work is

y -(-8) + 8 = -6x + 12 + 8

subtracting a negative is adding

y+8

They should subtract 8 from each side instead of adding 8 to each side

The student should have simplified the equation to have y + 8 on the left.

Then, the student should have subtracted 8 from both sides of the equation.

The value of b should be 4, not 20.

Step-by-step explanation:

ghjmutmum

step-by-step explanation:

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.