Consider the equation 4+2(5x-8) = ax +b.
For what values of a and b would the equation have infinitely many solutions?

a = 10, b = -12

Step-by-step explanation:

4+2(5x-8) = ax +b

4 + 10x - 16 = ax + b

10x - 12 = ax + b

Infinitely many solutions when:

a = 10

b = -12

a= 10

b = -12

Step-by-step explanation:

4+2(5x-8) = ax +b.

4+10x-16 = ax + b

4-16+10x = ax+b

-12+10x= ax+b

10x+(-12)= ax+b

ax= 10x

a= 10

b = -12

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

answer: plz put a pic in so i can answer it

step-by-step explanation: