A balloon ascending at a rate of 12ft/s is at a height of 80ft above the ground when a package is dropped. How long does it take the package to reach the ground? (Hint: the acceleration due to gravity is 32ft/s2 downward. Use antiderivatives.) You may leave your answer in radical form.

t = 2.64 or

Step-by-step explanation:

v(t) =

v(t) = -32t + C

when t = 0, the velocity is 12

12 = -32(0) + C

C = 12

v(t) = -32t + 12

now finding position

when t = 0, position is 80

80 = 0 + C, C = 80

now finding when position = 0

0 =

0 =

t = -1.89, 2.64

t>0, so t = 2.64

add an image

step-by-step explanation:

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol