Carter randomly selected some red and yellow clothing items at a store and recorded their prices. The tables below show the data he recorded in dollars.

Place each statement in the correct location on the table to show it is strongly supported by the data or it is not strongly supported by the data.

You have to compare if true some of the statements.

Most of these type questions would be compare the first three data

1. Prices of red to yellow mean we need to add them all up to begin with. 10 x £29.95 + 5 x 35.99 etc. = 15 items or add one zero (x10) to 29.95 and for 35.99 we add zero (x10) then divide by  2  ie) 359.9/2 = 360/2-0.2 = 180 - 0.2 = $179.98

2. Higher and lower comparisments we just take away from total.

3. The difference or how much more something is we subtract from the full total.

This would be a 4 way thought process below;

1. Prices in $ could mean groups, mean high or low we need to count how many items and add up all the prices to find the mean by adding them together.

2. Colour's could mean more red than yellow over a certain price or under a certain price.

3. Colour could also mean how many as a combined data were higher or lower than a certain price. ie) Higher than $29.99 would mean all the data set at $30.00  more. LEss would mean lower than $29.98

4. Mean and fx would be all the prices added together + all the items togather for the fx we multiply the individual groups and create a new box. We then multiple it to the other totals. This can also help establish or be compared to the percentage for advanced data tables.

Step-by-step explanation:

what graph

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)