5 times a number is 14 less than the square of that number. Find the positive solution.

PLEASE ANSWER

Write the word problem in algebraic form:

n2 -14 = 5n

Write as a quadratic:

n2 - 5n - 14 = 0

Factor:

(n+2)(n-7) = 0

Solve:

n+2 = 0    =>   n = -2

n-7 = 0    =>   n = 7

positive solution is 7.   (14 less than 72 = 35 which is also 5 times 7)

The positive solution is 7.

Step-by-step explanation:

Let the number be x, then we have:

5x = x^2 - 14

x^2 - 5x - 14 = 0

(x - 7)(x + 2) = 0

x =7, -2.

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

it is x equals 3   plese mark me really need it

step-by-step explanation: