24^2 = 20^2 +34^2-2(20)(34) cos(Q)
576 = 400+ 1156-(1360)cos(Q)
576 = 1556-(1360) cos(Q)
-980 = -(1360)COS(Q)

Your answer should be 49.

unless if u could do my questions, if not i wouldn't want to

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204