Factor the expression completely over the complex numbers. y^3+2y^2+16y+32

Please show all work thx:)

  (y +2)(y +4i)(y -4i)

Step-by-step explanation:

This lends itself to factoring by grouping. Then the quadratic factor can be considered to be the difference of squares and factored accordingly.

  (y^3 +2y^2) +(16y +32) = y^2(y +2) +16(y +2) = (y^2 +16)(y +2)

  = (y +2)(y^2 -(√-16)^2) = (y +2)(y^2 -(4i)^2)

  = (y +2)(y -4i)(y +4i)

lo.lll

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)