Find the dimensions of the rectangle.

Step-by-step explanation:

let width=w

length=3w-1

area=w(3w-1)=310

3w²-w-310=0

3w²-31w+30w-310=0

w(3w-31)+10(3w-31)=0

(3w-31)(w+10)=0

w=-10(rejected),31/3

length=31/3×3-1=31-1=30

length=30 ft

width=31/3 ft=10 1/3 ft

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

answer: idk

step-by-step explanation: