A homeowner is installing a swimming pool. You have been asked to install a circuit to operate a 600-watt underwater light and a circulating pump. The motor nameplate reveals that the pump has a current draw of 8.5 amperes. The devices are considered continuous duty. Can the power to operate both of these devices be supplied by a single 20-ampere circuit?

The answer is given below

Step-by-step explanation:

The loads in the circuit are continuous duty, so the circuit can only loaded to 80% of its current rating.

Calculate 80% current rating of the circuit breaker.

Icb = [ 80/100] (20 A)

     =  (O.8) (20 A )

     = 16 A

Now we assume that the value of supply voltage is 120 V

Now we will calculate current flows via under water light which will be taken as  Load 1

Ii = 500 W/120 V

  = 4.167 A

Current via the circulating pump which will be taken as Load 2 IS 8.5 A

I = load1 + load 2

   = 4.167 A + 8.5 A

  = 12.67 A

The total current in the circuit obtained which is less than the circuit breaker rating current. Therefore, the power can be operated for both the loads.

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

i dont know the answer but here's a picture of a dog