The opposition to current in an electrical circuit is called its impedance. the impedance z in a parallel circuit with two pathways satisfies the equation: 1/z + 1/z1 + 1/z2 where z1 is the impedance (in ohms) of pathway 1 and z2 is the impedance of pathway 2.
a) the impedance of each pathway in a parallel circuit is found by adding the impedances of all components in the pathway. use the table to find z1 and z2.
b) find the impedance z.
(diagram drawn)

a 1/z1 = 1/bi

 1/z2 = -1/ci

b impedance z = 1/z = [(1/a)² + (-1/ci -1/bi)²]^1/2

Step-by-step explanation:

circuit in parallel

a for the resistor impedance  = 1/z = 1/ a

for the inductor inductance   = 1/ bi = 1/xL

for the capacitor capacitance  = - 1/ci = 1/xc

the reactances  is the INDUCTANCE AND CAPACITANCE

The impedance = 1/z = [ (-1/ci -1/bi)²]^1/2

Since the circuit is parallel impedance z across the pathway is given by

b impedance z = 1/z = [(1/a)² + (-1/ci -1/bi)²]^1/2

the aswere is the one with all 8's and the second one is with the 10,8 and 6

step-by-step explanation: