Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a radius of 7 feet and a height of 14 feet. Container B has a radius of 8 feet and a height of 10 feet. Container A is full of water and the water is pumped into Container B until Conainter B is completely full. After the pumping is complete, what is the volume of water remaining in Container A, to the nearest tenth of a cubic foot? play

the volume of water remaining in Container A is 144.4ft³

Step-by-step explanation:

The formula for determining the volume of a cylinder is expressed as

Volume = πr²h

Where

r represents the radius of the cylinder.

h represents the height of the cylinder.

π is a constant whose value is 3.14

Considering container A,

Radius = 7 feet

Height = 14 feet

Therefore,

Volume of water in a completely filled container A is

3.14 × 7² × 14 = 2154.04 ft³

Considering container B,

Radius = 8 feet

Height = 10 feet

Volume of water that will fill container B is

3.14 × 8² × 10 = 2009.6 ft³

Therefore, the volume of water remaining in Container A is

2154.04 - 2009.6 = 144.4ft³

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

gimme brainliest > : 3

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.