Which series of transformations shows that quadrilateral A is congruent to quadrilateral B? A. Reflect quadrilateral A over the x-axis, translate it 5 units to the right, and reflect it over the x-axis. B. Translate quadrilateral A 3 units up, translate it 2 units to the left, and rotate it 180° clockwise about the origin. C. Translate quadrilateral A 3 units up, translate it 2 units to the left, and reflect it over the y-axis. D. Rotate quadrilateral A 90° counterclockwise about the origin, translate it 5 units up, and reflect it over the y-axis

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

vertical asymptote .

horizontal asymptote .

step-by-step explanation:

given function is .

vertical asymptote is given by setting

denominator =0

when degree of numerator and denominator are same then divide first term of numerator by first term of denominator to get horizontal asymptote.

answer: i ! the answer is   9000 seconds, also d

hope i

-lavira : )

the value of x is 28.2