If a cylindrical bar has radius 2m and height 9cm and if it is melted and become a sphere. what is the radius of the sphere?

Volume of the Cylindrical bar, V = pi * r^2 * h
V = pi * 200^2 * 9
V = 22/7 * 40000 * 9

Let's assume the radius of the sphere as r
Volume of the sphere V1 = 4/3 * pi * r^3
V1 = V
V1 = 4/3 * pi * r^3
22/7 * 40000 * 9 = 4/3 * 22/7 * r^3
r^3 = (40000 * 9) * 3/4
r^3 = 10000 * 9 * 3
r = ( 10 * 10^3 * 3^3)^(1/3)
r = 10^(1/3) * 10 * 3
r = 2.154 * 30
r =  64.63 cm

For a 0.25 pfor b o.3pp (0.25+0.3)=0.28