Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading less than -0.23°C. Round your answer to 4 decimal places P ( Z < − 0.23 ) =

P(x > - 0.23) = 0.41

Step-by-step explanation:

Since we are assuming that the readings at freezing on a batch of thermometers are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = the readings at freezing on a batch of thermometers.

µ = mean temperature reading

σ = standard deviation

From the information given,

µ = 0°C

σ = 1.00°C

the probability of obtaining a reading less than -0.23°C is expressed as

P(x > - 0.23)

For x = - 0.23

z = (- 0.23 - 0)/1 = - 0.23

Looking at the normal distribution table, the probability corresponding to the z score is 0.41

side xy = 10

sin(x) = 4/5

cos(x) = 3/5

tan(x) = 4/3

step-by-step explanation:

898.1666667

step-by-step explanation:

5389/6 = 898.1666667