Which point is the vertex of the quadratic function f(x)=x2−6x+8?

vertex: (3 , -1)

Step-by-step explanation:

x²−6x+8 = (x²−6x+9) -9 +8 = (x-3)² - 1

equation: f(x) =a (x - h)² + k    (h,k) is vertex

f(x) = (x-3)² - 1

vertex: (3 , -1)

a.

step-by-step explanation:

step 1 distribute 2 to every term in the parentheses

step 2 add 10 on both sides of the equal sign