The sum of ages the ages of yao and kwao is 29 years. yao is 3 years older than kwame. how old are the two people

Yao is 16 years old

Kwame is 13 years old

Step-by-step explanation:

Let's assume Kwame's age to be x

Yao is 3 years older than Kwame, this means Yao's age is x + 3

The sum of their ages is 29

Hence, x + (x + 3) = 29

x + x + 3 = 29

2x + 3 = 29

Next, we collect like terms by subtracting 3 from both sides of the equation

2x + 3 - 3 = 29 - 3

2x = 26

We then divide both sides of the equation by the coefficient of x

2x/2 = 26/2

x = 13

This means Kwame's age is 13

Yao is 3 years older than Kwame, Yao is 13 + 3 = 16 years old

b

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)