Alison is making a 16 inch necklace. The first 4 1/4 inches filled with red beads and 8 3/8 inches are filled with blue beads. The rest has white beads. How many inches are filled with white beads

Step-by-step explanation:

Given:

Alison is making a 16 inch necklace.

The first 4 1/4 inches filled with red beads.

And 8 3/8 inches are filled with blue beads.

The rest has white beads.

Question asked:

How many inches are filled with white beads ?

Solution:

Total length of necklace in inches = 16

Length of necklace filled with red beads in inches =

Length of necklace filled with blue beads in inches =

Length of necklace filled with white beads in inches = Total length of necklace - (Length of necklace filled with red beads + Length of necklace filled with blue beads)

Length of necklace filled with white beads in inches

Thus, are filled with white beads in  necklace.

54.864 meters

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.