Factor –8x3 – 2x2 – 12x – 3 by grouping. What is the resulting expression?
(2x2 – 3)(4x + 1)
(–2x2 – 3)(–4x + 1)
(2x2 – 3)(–4x + 1)
(–2x2 – 3)(4x + 1)

The answer to your question is the last option   (-2x² - 3)(4x + 1)

Step-by-step explanation:

Expression              - 8x³ - 2x² - 12x - 3

Order the terms     - 8x³ - 12x - 2x² - 3

Process

1.- Factor the first two terms and the last two terms

                               (-8x³ - 12x²) + (-2x - 3)

Common factor of the first group   -4x

Common factor of the second group   -1

2.- Factor each group

First group                  -4x(2x² + 3)

Second group            -1 (2x² + 3)

3.- Factor again by common factor

                         -4x(2x² + 3) - 1(2x² + 3)

                         (2x² + 3)(-4x - 1)  or -(2x² + 3)(4x + 1) or (-2x² - 3)(4x + 1)

d       ik

Step-by-step explanation:

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation:

2425

step-by-step explanation: