Slope of a line that goes through the points (-5,-5) and (-5,5)

Slope = 0

Step-by-step explanation:

The equation of the line

y = mx + c

y = intercept point y

m = slope of the line

x = intercept point x

c = intercept

Given two points

( -5 , -5) ( -5 , -5)

x1 = -5

y1 = -5

x2 = -5

y2 = -5

Insert the values into

m = y2 - y1 / x2 - x1

m = -5 - (-5) / -5 - (-5)

= -5 + 5 / -5 + 5

= 0/ 0

= 0

The slope of the line is 0

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.