Someone i beg of you help me with this please:
Isabella wants to use dragons and unicorns by giving them joke books. She wants to amuse a total of at least 14 dragons and unicorns (Condition A), with 108 joke books at most (condition B). The graph represents the constraints on the number of dragons D and unicorns U Isabella amuses. Isabella amuses 2 dragons. How many unicorns can she amuse to meet both her constraints?
A.) Exactly 15 unicorns
B.) Isabella doesn’t have enough joke booked left to amuse any unicorns
C.) At least 14 unicorns and at most 18 unicorns
D.6 At lest 12 unicorns and at most 15 unicorns

what is the rest of the question? ?

need more info

step-by-step explanation:

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.