An object is dropped from the top of a tower with a height of 1120 feet. Neglecting air resistance, the height of the object at time t seconds is given by the polynomial -16t^2+1120 find the height of the object at t=7 seconds ight of the object at time t seconds is given by the polynomial negative 16 t squared plus 1120. Find the height of the object at t equals 7 seconds

The height of the object at t=7 seconds is 336 feet.

Step-by-step explanation:

Given,

An object is dropped from the top of a tower with a height of height of 1120 feet.

The height of the object at time t second is given by the polynomial

h(t)= -16t² +1120

To find the height, we put the value of t=7 in the above equation

h(7)= - 16(7)²+1120

    = 336 feet.

The height of the object at t=7 seconds is 336 feet.

Height of the object after 7 seconds would be 336 feet.

Step-by-step explanation:

Given:

Height of the tower = 1120 ft

We need to find the height of the object after 7 seconds.

Solution:

To find the height of the object after 7 seconds we will substitute t = 7 secs

So we can say that;

Hence We can say that;

Height of the object after 7 seconds would be 336 feet.

a: inscribed angles

step-by-step explanation:

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