The tables represent two linear functions in a system.

the tables are:
x | y x y
| |
-6 |-22 -6 | -30
-3 |-10 -3 | -21
0 |2 0 | -12
3 |14 3 | -3

what is the solution to this system?
/3,-25)
/3,-54)
,-50)
,-54)

For the first table, y-intercept = 2, slope = (14 - 2)/3 = 12/3 = 4
Hence, equation is y = 4x + 2

For second table, y-intercept = -12, slope = (-3 - (-12))/3 = (-3 + 12)/3 = 9/3 = 3
Hence, equation is y = 3x - 12

Therefore, the solution is
4x + 2 = 3x - 12
x = -14, and y = 4(-14) + 2 = -56 + 2 = -54
(-14, -54)