According to Newton’s Law of cooling, the temperature of an object decreases at a rate proportional to the difference between its temperature and that of the surrounding air. Suppose a corpse at a temperature of 32° C arrives at a mortuary where the temperature is kept at 10°C. Then the equation satisfying the temperature T of the corpse t hours later is:.

dT / dt = - 22 * k

Step-by-step explanation:

Newton's law tells us that:

dT / dt = - k * (T - A)

Being dT / dt the change with respect to time.

"k" would be the speed constant, in this case we do not know it.

"T" the temperature of the object to be observed, in this case the corpse that is 32 ° C

And "A" is the ambient temperature, which in this case is the temperature at which the morgue is maintained, which is 10 ° C.

Replacing:

dT / dt = - k * (32 - 10)

dT / dt = - 22 * k

"k" must be in hours ^ (- 1) and this would be the expression that satisfies the temperature T of the corpse t hours later.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)