A box of 15 chocolates has 6 that are caramel, 5 that contain nuts, and 4 that are nougat. If you randomly select 3 chocolates, what is the probability that you will get all nuts?

0.849

Step-by-step explanation:

Number of caramel Chocolates= 6 Chocolates

Number of nut Chocolates= 5 Chocolates

Number of nougat= 4 chocolates

Total number of chocolates= 15

so, we have to find the probability of randomly selected 3 chocolates that are nuts

When first chocolate is drawn

P(nut chocolates)=

Now second chocolate is drawn

P(nut chocolates)=

When the  third chocolate is drawn

P(nut chocolates)=

Total probability =+ +

Total probability= 0.849

Hence, the correct answer is 0.849

hi,

i'm 75% sure the answer is 1,1 to both lines.

have a great day

16.9 times 2.85

step-by-step explanation: