Two machines turn out all the products in a factory, with the first machine producing 40%of the product and the second 60%. The first machine produces defective products 2% of the timeand the second machine 4% of the time. Given a defective product, what is the probability it wasproduced on the first machine

0.4

Step-by-step explanation:

First Machine(M1) Produces 40% of the product.

P(M1)=40%=0.4

The first Machine Produces defective product(D) 2% of the Time.

P(D)=2%=0.02

Given a defective product(D), we want to find the probability that it was produced on the first machine(M1).

P(M1|D)=P(M1∩D)/P(D)

=(0.4 X 0.02)/0.02

=0.4

.24

step-by-step explanation:

the probability is   .24

the first player had the highest probability of getting a silver marble

the game could be made fair by adding back the marble that was drawn after each draw

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.