Write a quadratic function that has a graph that contains the following points, (-2, 0), (4, -12), (5,0).

f(x) =  2x^2 - 6x - 20.

Step-by-step explanation:

(-2, 0) and (5, 0)  are 2 zeroes of the function so we can write the function as

f(x) =  a(x + 2)(x - 5)   where a is a constant.

Now as (4, -12) is a point on the graph:

-12 = a(4 + 2)(4 - 5)

-12 = a * 6 * -1

-6a = -12

a = 2.

So f(x) = 2(x + 2)(x - 5)

f(x) =  2x^2 - 6x - 20.

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d

351°f

step-by-step explanation: