Find all the complex zeros for the polynomial function. show work
f(x)=x^3-7x^2+x-7

  ±i

Step-by-step explanation:

Observing that the first two coefficients are the same as the last two, we can factor this function by grouping.

  f(x) = (x^3 -7x^2) +(x -7) = x^2(x -7) +1(x -7)

  f(x) = (x^2 +1)(x -7)

The factor x-7 has a real zero at x=7, so the complex zeros come from the quadratic factor (x^2 +1).

Setting that to zero and solving for x, we find ...

  x^2 +1 = 0

  x^2 = -1

  x = ±√(-1) = ±i

The complex zeros are x = +i and x = -i.

total of apples - take away four

6-4 = 2

answer is 2 apples

∡ eia and ∡ kij are congruent

step-by-step explanation: