A tire manufacturer warranties its tires to last at least 20,000 miles orâ "you get a new set ofâ tires." In itsâ experience, a set of these tires last on average 26,000 miles with SD 5,000 miles. Assume that the wear is normally distributed. The manufacturer profits â$200 on each setâ sold, and replacing a set costs the manufacturer â$400. Complete parts a through c.
(a) What is the probability that a set of tires wears out before 20,000 miles?

Probability that a set of tires wears out before 20,000 miles is 0.1151.

Step-by-step explanation:

We are given that a tire manufacturer warranties its tires to last at least 20,000 miles or "you get a new set of tires." In its past experience, a set of these tires last on average 26,000 miles with S.D. 5,000 miles. Assume that the wear is normally distributed.

Let X = wearing of tires

So, X ~ N()

Now, the z score probability distribution is given by;

         Z = ~ N(0,1)

where, = average lasting of tires = 26,000 miles

            = standard deviation = 5,000 miles

So, probability that a set of tires wears out before 20,000 miles is given by = P(X < 20,000 miles)

    P(X < 20,000) = P( < ) = P(Z < -1.2) = 1 - P(Z 1.2)

                                                                    = 1 - 0.88493 = 0.1151

Therefore, probability that a set of tires wears out before 20,000 miles is 0.1151.

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x

your answer is

a.

5

step-by-step explanation: