Find the probability of drawing a 10, replacing it, and drawing an ace.

Assuming that you're talking about a standard deck of 52 cards, there are 4 tens and 4 aces.

So, at the beginning, you have probability 4/52=1/13 to draw a ten.

You replace, and you have an identical probability to draw an ace (you still have 4 favourable cases over 52 total cases).

Multiply the two probabilities to find the

answer: 2/4

step-by-step explanation:

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a