The circumference of a sphere was measured to be 70 cm with a possible error of 0.5 cm. (a) Use differentials to estimate the maximum error in the calculated surface area. (Round your answer to the nearest integer.) cm2 What is the relative error

Therefore the maximum error in the surface area of the sphere is 22.27 cm².

Therefore the relative error is 0.014 (approx).

Step-by-step explanation:

Given that, The circumference of a sphere was 70 cm with the possible error 0.5 cm.

The circumference of the sphere is C

∴C  

Differentiating with respect to r

   [ relative error = dC= 0.5]

The surface area of the sphere is S=

∴S=

Differentiating with respect to r

dS will be maximum when dr is maximum.

Putting the value of r and dr

    [ ∵ C= 70 ]

⇒dS= 22.27 (approx)

Therefore the maximum error in the surface area is 22.27 cm².

Relative error

                    =0.014 (approx)

Therefore the relative error is 0.014 (approx).

answer: rolling a number cube and flipping a coin.

step-by-step explanation:

vertical asymptote .

horizontal asymptote .

step-by-step explanation:

given function is .

vertical asymptote is given by setting

denominator =0

when degree of numerator and denominator are same then divide first term of numerator by first term of denominator to get horizontal asymptote.