On maths watch I need the answer for In the Diagram AB=BC=CD=DA Prove that triangle ADB is congruent to CDB.

Since , the figure is a rhombus. This implies that opposite angles are congruent. In particular, we have angle A is congruent to angle C.

So, triangle ADB and triangle CDB have two sides in common (AD=CD and AB=BC), and the angle between those side in common (angle A=angle C).

So, by the SAS criterion, they are congruent.

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)