How do i solve 4X598 with distributive property

1. Multiply the term outside of the parentheses by each term in the parentheses. To do this, you are essentially distributing the outer term into the inner terms. Multiply the term outside the parentheses by the first term in the parentheses. Then multiply it by the second term. If there are more than two terms, keep distributing the term until there are no terms left. Keep whatever operation (plus or minus) is in the parentheses.

2(x-3)=10}2(x-3)=10

2(x)-(2)(3)=10}2(x)-(2)(3)=10

2x-6=10

2. Combine like terms. Before you can solve the equation, you will have to combine like terms. Combine all numerical terms with each other. Separately, combine any variable terms. To simplify the equation, arrange the terms so the variables are on one side of the equals sign and the constants (numbers only) are on the other.[2]

2x-6=10}2x-6=10…..(original problem)

2x-6(+6)=10(+6)}2x-6(+6)=10(+6)….. (Add 6 to both sides)

2x=16}2x=16….. (Variable on left; constant on right)

3. Solve the equation. Solve for {\displaystyle x}x by dividing both sides of the equation by the coefficient in front of the variable.[3]

2x=16}2x=16…..(original problem)

2x/2=16/2}2x/2=16/2…..(divide both sides by 2)

x=8}x=8…..(solution)

the answer is a

step-by-step explanation:

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.