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Mathematics, 22.03.2020 21:10 tdyson3p6xvtu

Given two functions j(x)=βˆ’3x+2 and k(x)=3+4x , what is the function rule for (kj)(x) ?

A. (kj)(x)=βˆ’12x^2+18x+6

B. (kj)(x)=βˆ’12x^2+xβˆ’6

C. (kj)(x)=βˆ’12x^2βˆ’x+6

D. (kj)(x)=12x^2βˆ’18xβˆ’6

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Given two functions j(x)=βˆ’3x+2 and k(x)=3+4x , what is the function rule for (kj)(x) ?

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