Henry rolls 2 number cubes numbered 1 through 6 while playing his favorite board game. he will get a second turn if he rolls a sum that is an even number less than 10. what are henry’s chances of getting a second turn when he rolls the number cubes

Henry has 13 chances to get a second turn.

Step-by-step explanation:

When two number cubes numbered from 1 to 6 are rolled, the number of possible outcomes are 36.

The 36 possible outcomes are as follows :

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6).

It is given that, Henry gets the second turn if he rolls a sum that is an even number less than 10.

Therefore, the even numbers less than 10 are {2,4,6,8}.

Check for the sum of outcomes that gives the result of even number less than 10.

Sum of (1,1) (1,3) (1,5) gives 2,4,6 which are even numbers less than 10 ⇒ 3 chances.Sum of (2,2) (2,4) (2,6) gives 4,6,8 which are even numbers less than 10 ⇒ 3 chances.Sum of (3,3) (3,5) gives 6 and 8 which are even numbers less than 10 ⇒ 2 chances.Sum of (4,2) (4,4) gives 6 and 8 which are even numbers less than 10 ⇒ 2 chances.Sum of (5,1) (5,3) gives 6 and 8 which are even numbers less than 10 ⇒ 2 chances.Sum of (6,2) gives 8 which is a even number less than 10 ⇒ 1 chance.

The total number of chances to get second turn = 3+3+2+2+2+1 = 13 chances.

Therefore, Henry has 13 chances to get a second turn.

4+2=-2. 1+2=3. y=-2/3x+b. 2=4/3+b. 2/3=b. the answer is y= -2/3x+2/3

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