From the set of points {(-4, 4), (0, 3), (5, 1), (7, 0)}, which ordered pairs are part of the solution set for 3x - 4y < -4 ? Reminder: To be a part of the solution, the ordered pair must make the inequality true. Plug in the x and the y and see if it makes a true statement. Group of answer choices {(-4, 4), (5, 1)} {(0, 3), (7, 0)} {(5, 1), (7, 0)} {(-4, 4), (0, 3)}

The group of points that satisfies the equation 3x - 4y < - 4 is {(-4,4), (0,3)}.

Step-by-step explanation:

The first point is (-4,4) and putting those values in the left hand side of the inequality equation, we get,

3(-4) - 4(4) = - 12 - 16 = - 28 < - 4

Now, the second point is (0,3) and putting those values in the left hand side of the inequality equation, we get,

3(0) - 4(3) = - 12 < - 4.

Therefore, the group of points that satisfies the equation 3x - 4y < - 4 is {(-4,4), (0,3)}. (Answer)

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.